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X^2+225+99X=25
We move all terms to the left:
X^2+225+99X-(25)=0
We add all the numbers together, and all the variables
X^2+99X+200=0
a = 1; b = 99; c = +200;
Δ = b2-4ac
Δ = 992-4·1·200
Δ = 9001
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(99)-\sqrt{9001}}{2*1}=\frac{-99-\sqrt{9001}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(99)+\sqrt{9001}}{2*1}=\frac{-99+\sqrt{9001}}{2} $
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